JUST IN:MOTOGP LEGEND GIANCARLO AGOSTINI WEIGHS IN ON….

JUST IN:MOTOGP LEGEND GIANCARLO AGOSTINI WEIGHS IN ON….

MotoGP legend Giacarlo Agostini has laid down the gauntlet for Francesco Bagnaia, saying that the Ducati rider must beat Marc Marquez to prove himself as a genuine title contender.

Agostini, who won 15 world championships during his illustrious career, believes that Bagnaia has the talent and the machinery to win the MotoGP title, but he must first overcome the hurdle of Marquez, who has dominated the sport in recent years.

“Bagnaia is a very talented rider, and he has a great bike in the Ducati,” Agostini said in an interview. “But to win the title, he must beat Marquez. Marc is a fantastic rider, and he has a lot of experience. He knows how to win championships, and he will not give up easily.”

Agostini’s comments come after Bagnaia’s impressive performance at the recent MotoGP test in Valencia, where he topped the timesheets on the final day. However, Agostini believes that Bagnaia must translate his testing form into results on the track if he is to have any chance of winning the title.

“Testing is one thing, but racing is another,” Agostini said. “Bagnaia must be able to perform under pressure, and he must be able to beat Marquez in a straight fight. If he can do that, then he will be a genuine title contender.”

Bagnaia has been tipped by many as a potential title winner in 2024, and Agostini’s comments will only add to the pressure on the Italian rider. However, Bagnaia has shown in the past that he has the talent and the temperament to handle the pressure, and he will be looking to make a strong start to the season when the lights go out in Portugal.

In conclusion, Agostini’s comments have set the bar high for Bagnaia, and the Italian rider will be looking to prove himself as a genuine title contender when the MotoGP season gets underway. With Marquez and other top riders waiting in the wings, Bagnaia will need to be at the top of his game if he is to achieve his goal of winning the MotoGP title.